Adam has 3 times as many stickers as Bryan.
After Bryan buys another 120 stickers,
he has 3 times as many stickers as Adam.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
3 u |
1 u |
Change |
No change |
+ 120 |
After |
3 u |
9 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of stickers that Bryan buys
= 9 u - 1 u
= 8 u
8 u = 120
1 u = 120 ÷ 8 = 15
Number of stickers that Bryan has in the end
= 9 u
= 9 x 15
= 135
(b)
Number of stickers that Adam has at first
= 3 u
= 3 x 15
= 45
(c)
Number of stickers that they have at first
= 3 u + 1 u
= 4 u
= 4 x 15
= 60
(d)
Number of stickers that they have in the end
= 3 u + 9 u
= 12 u
= 12 x 15
= 180
Answer(s): (a) 135; (b) 45; (c) 60; (d) 180