Adam has 2 times as many stickers as Bryan.
After Bryan buys another 55 stickers,
he has 3 times as many stickers as Adam.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
| |
Adam |
Bryan |
| Before |
2 u |
1 u |
| Change |
No change |
+ 55 |
| After |
2 u |
6 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Bryan buys
= 6 u - 1 u
= 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
Number of stickers that Bryan has in the end
= 6 u
= 6 x 11
= 66
(b)
Number of stickers that Adam has at first
= 2 u
= 2 x 11
= 22
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 11
= 33
(d)
Number of stickers that they have in the end
= 2 u + 6 u
= 8 u
= 8 x 11
= 88
Answer(s): (a) 66; (b) 22; (c) 33; (d) 88
