Charlie has 3 times as many stickers as Adam.
After Charlie gives away 45 stickers,
Adam has 2 times as many stickers as Charlie.
- How many stickers does Adam have?
- How many stickers does Charlie have at first?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
6 u |
2 u |
Change |
- 45 |
No change |
After |
1 u |
2 u |
(a)
The number of stickers Adam at first and in the end remains unchanged.
Make the number of stickers that Adam has the same using LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Charlie gives away
= 6 u - 1 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Number of stickers that Adam has
= 2 u
= 2 x 9
= 18
(b)
Number of stickers that Charlie has at first
= 6 u
= 6 x 9
= 54
(c)
Number of stickers that they have at first
= 6 u + 2 u
= 8 u
= 8 x 9
= 72
(d)
Number of stickers that they have in the end
= 1 u + 2 u
= 3 u
= 3 x 9
= 27
Answer(s): (a) 18; (b) 54; (c) 72; (d) 27