Adam has 2 times as many stickers as Charlie.
After Adam gives away 27 stickers,
Charlie has 2 times as many stickers as Adam.
- How many stickers does Charlie have?
- How many stickers does Adam have at first?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
4 u |
2 u |
Change |
- 27 |
No change |
After |
1 u |
2 u |
(a)
The number of stickers Charlie at first and in the end remains unchanged.
Make the number of stickers that Charlie has the same using LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Adam gives away
= 4 u - 1 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
Number of stickers that Charlie has
= 2 u
= 2 x 9
= 18
(b)
Number of stickers that Adam has at first
= 4 u
= 4 x 9
= 36
(c)
Number of stickers that they have at first
= 4 u + 2 u
= 6 u
= 6 x 9
= 54
(d)
Number of stickers that they have in the end
= 1 u + 2 u
= 3 u
= 3 x 9
= 27
Answer(s): (a) 18; (b) 36; (c) 54; (d) 27