Adam has 2 times as many stickers as Bryan.
After Adam gives away 40 stickers,
Bryan has 3 times as many stickers as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
6 u |
3 u |
Change |
- 40 |
No change |
After |
1 u |
3 u |
(a)
The number of stickers Bryan at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of stickers that Adam gives away
= 6 u - 1 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of stickers that Bryan has
= 3 u
= 3 x 8
= 24
(b)
Number of stickers that Adam has at first
= 6 u
= 6 x 8
= 48
(c)
Number of stickers that they have at first
= 6 u + 3 u
= 9 u
= 9 x 8
= 72
(d)
Number of stickers that they have in the end
= 1 u + 3 u
= 4 u
= 4 x 8
= 32
Answer(s): (a) 24; (b) 48; (c) 72; (d) 32