Bryan has 2 times as many stickers as Adam.
After Adam gives away 90 stickers,
Bryan has 5 times as many as Adam.
- How many stickers does Adam have in the end?
- How many stickers does Bryan have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Adam |
Before |
10 u |
5 u |
Change |
No change |
- 90 |
After |
10 u |
2 u |
(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the number of stickers Bryan has the same using LCM of 2 and 5
LCM of 2 and 5 = 10
Number of stickers that Adam gives away
= 5 u - 2 u
= 3 u
3 u = 90
1 u = 90 ÷ 3 = 30
Number of stickers that Adam has in the end
= 2 u
= 2 x 30
= 60
(b)
Number of stickers that Bryan has
= 10 u
= 10 × 30
= 300
(c)
Number of stickers that they have at first
= 10 u + 5 u
= 15 u
= 15 x 30
= 450
(d)
Number of stickers that they have in the end
= 10 u + 2 u
= 12 u
= 12 x 30
= 360
Answer(s): (a) 60; (b) 300; (c) 450; (d) 360