Adam has 2 times as many stickers as Bryan.
After Bryan gives away 30 stickers,
Adam has 5 times as many as Bryan.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
10 u |
5 u |
Change |
No change |
- 30 |
After |
10 u |
2 u |
(a)
The number of stickers Adam has at first and in the end remains unchanged.
Make the number of stickers Adam has the same using LCM of 2 and 5
LCM of 2 and 5 = 10
Number of stickers that Bryan gives away
= 5 u - 2 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of stickers that Bryan has in the end
= 2 u
= 2 x 10
= 20
(b)
Number of stickers that Adam has
= 10 u
= 10 × 10
= 100
(c)
Number of stickers that they have at first
= 10 u + 5 u
= 15 u
= 15 x 10
= 150
(d)
Number of stickers that they have in the end
= 10 u + 2 u
= 12 u
= 12 x 10
= 120
Answer(s): (a) 20; (b) 100; (c) 150; (d) 120