Bryan has 2 times as many stickers as Adam.
After Adam gives away 90 stickers,
Bryan has 5 times as many as Adam.

1. How many stickers does Adam have in the end?
2. How many stickers does Bryan have?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Bryan	Adam
Before	10 u	5 u
Change	No change	- 90
After	10 u	2 u

(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the number of stickers Bryan has the same using LCM of 2 and 5 
LCM of 2 and 5 = 10

Number of stickers that Adam gives away
= 5 u - 2 u
= 3 u

3 u = 90

1 u = 90 ÷ 3 = 30

Number of stickers that Adam has in the end
= 2 u
= 2 x 30
= 60

(b)
Number of stickers that Bryan has
= 10 u
= 10 × 30
= 300

(c)
Number of stickers that they have at first
= 10 u + 5 u
= 15 u
= 15 x 30
= 450

(d)
Number of stickers that they have in the end
= 10 u + 2 u
= 12 u
= 12 x 30
= 360

Answer(s): (a) 60; (b) 300; (c) 450; (d) 360