Bryan has 5 times as many stickers as Adam.
After Adam receives another 40 stickers,
both have equal number of stickers.
- How many stickers does Adam have in the end?
- How many stickers does Bryan have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
| |
Bryan |
Adam |
| Before |
5 u |
1 u |
| Change |
No change |
+ 40 |
| After |
5 u |
5 u |
(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the numer of stickers that Bryan has the same using LCM of 1 and 5.
LCM of 1 and 5 = 5
Number of stickers that Adam receives
= 5 u - 1 u
= 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Number of stickers that Adam has in the end
= 5 u
= 5 x 10
= 50
(b)
Number of stickers that Bryan has at first
= 5 u
= 5 x 10
= 50
(c)
Number of stickers that they have at first
= 1 u + 5 u
= 6 u
= 6 x 10
= 60
(d)
Number of stickers that they have in the end
= 5 u + 5 u
= 10 u
= 10 x 10
= 100
Answer(s): (a) 50; (b) 50; (c) 60; (d) 100
