Bryan has 3 times as many stickers as Charlie.
After Charlie receives another 20 stickers,
both have equal number of stickers.
- How many stickers does Charlie have in the end?
- How many stickers does Bryan have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Charlie |
Before |
3 u |
1 u |
Change |
No change |
+ 20 |
After |
3 u |
3 u |
(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the numer of stickers that Bryan has the same using LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of stickers that Charlie receives
= 3 u - 1 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Number of stickers that Charlie has in the end
= 3 u
= 3 x 10
= 30
(b)
Number of stickers that Bryan has at first
= 3 u
= 3 x 10
= 30
(c)
Number of stickers that they have at first
= 1 u + 3 u
= 4 u
= 4 x 10
= 40
(d)
Number of stickers that they have in the end
= 3 u + 3 u
= 6 u
= 6 x 10
= 60
Answer(s): (a) 30; (b) 30; (c) 40; (d) 60