Bryan has 3 times as many stickers as Charlie.
After Charlie receives another 30 stickers,
both have equal number of stickers.
- How many stickers does Charlie have in the end?
- How many stickers does Bryan have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
| |
Bryan |
Charlie |
| Before |
3 u |
1 u |
| Change |
No change |
+ 30 |
| After |
3 u |
3 u |
(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the numer of stickers that Bryan has the same using LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of stickers that Charlie receives
= 3 u - 1 u
= 2 u
2 u = 30
1 u = 30 ÷ 2 = 15
Number of stickers that Charlie has in the end
= 3 u
= 3 x 15
= 45
(b)
Number of stickers that Bryan has at first
= 3 u
= 3 x 15
= 45
(c)
Number of stickers that they have at first
= 1 u + 3 u
= 4 u
= 4 x 15
= 60
(d)
Number of stickers that they have in the end
= 3 u + 3 u
= 6 u
= 6 x 15
= 90
Answer(s): (a) 45; (b) 45; (c) 60; (d) 90
