Adam has 5 times as many stickers as Charlie.
After Charlie receives another 60 stickers,
both have equal number of stickers.
- How many stickers does Charlie have in the end?
- How many stickers does Adam have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Charlie |
Before |
5 u |
1 u |
Change |
No change |
+ 60 |
After |
5 u |
5 u |
(a)
The number of stickers Adam has at first and in the end remains unchanged.
Make the numer of stickers that Adam has the same using LCM of 1 and 5.
LCM of 1 and 5 = 5
Number of stickers that Charlie receives
= 5 u - 1 u
= 4 u
4 u = 60
1 u = 60 ÷ 4 = 15
Number of stickers that Charlie has in the end
= 5 u
= 5 x 15
= 75
(b)
Number of stickers that Adam has at first
= 5 u
= 5 x 15
= 75
(c)
Number of stickers that they have at first
= 1 u + 5 u
= 6 u
= 6 x 15
= 90
(d)
Number of stickers that they have in the end
= 5 u + 5 u
= 10 u
= 10 x 15
= 150
Answer(s): (a) 75; (b) 75; (c) 90; (d) 150