Bryan has 4 times as many stickers as Charlie.
After Charlie receives another 60 stickers,
both have equal number of stickers.
- How many stickers does Charlie have in the end?
- How many stickers does Bryan have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Charlie |
Before |
4 u |
1 u |
Change |
No change |
+ 60 |
After |
4 u |
4 u |
(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the numer of stickers that Bryan has the same using LCM of 1 and 4.
LCM of 1 and 4 = 4
Number of stickers that Charlie receives
= 4 u - 1 u
= 3 u
3 u = 60
1 u = 60 ÷ 3 = 20
Number of stickers that Charlie has in the end
= 4 u
= 4 x 20
= 80
(b)
Number of stickers that Bryan has at first
= 4 u
= 4 x 20
= 80
(c)
Number of stickers that they have at first
= 1 u + 4 u
= 5 u
= 5 x 20
= 100
(d)
Number of stickers that they have in the end
= 4 u + 4 u
= 8 u
= 8 x 20
= 160
Answer(s): (a) 80; (b) 80; (c) 100; (d) 160