Charlie has 3 times as many stickers as Adam.
After Adam receives another 60 stickers,
both have equal number of stickers.
- How many stickers does Adam have in the end?
- How many stickers does Charlie have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Charlie |
Adam |
Before |
3 u |
1 u |
Change |
No change |
+ 60 |
After |
3 u |
3 u |
(a)
The number of stickers Charlie has at first and in the end remains unchanged.
Make the numer of stickers that Charlie has the same using LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of stickers that Adam receives
= 3 u - 1 u
= 2 u
2 u = 60
1 u = 60 ÷ 2 = 30
Number of stickers that Adam has in the end
= 3 u
= 3 x 30
= 90
(b)
Number of stickers that Charlie has at first
= 3 u
= 3 x 30
= 90
(c)
Number of stickers that they have at first
= 1 u + 3 u
= 4 u
= 4 x 30
= 120
(d)
Number of stickers that they have in the end
= 3 u + 3 u
= 6 u
= 6 x 30
= 180
Answer(s): (a) 90; (b) 90; (c) 120; (d) 180