Charlie has 5 times as many stickers as Bryan.
After Bryan receives another 20 stickers,
both have equal number of stickers.
- How many stickers does Bryan have in the end?
- How many stickers does Charlie have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Charlie |
Bryan |
Before |
5 u |
1 u |
Change |
No change |
+ 20 |
After |
5 u |
5 u |
(a)
The number of stickers Charlie has at first and in the end remains unchanged.
Make the numer of stickers that Charlie has the same using LCM of 1 and 5.
LCM of 1 and 5 = 5
Number of stickers that Bryan receives
= 5 u - 1 u
= 4 u
4 u = 20
1 u = 20 ÷ 4 = 5
Number of stickers that Bryan has in the end
= 5 u
= 5 x 5
= 25
(b)
Number of stickers that Charlie has at first
= 5 u
= 5 x 5
= 25
(c)
Number of stickers that they have at first
= 1 u + 5 u
= 6 u
= 6 x 5
= 30
(d)
Number of stickers that they have in the end
= 5 u + 5 u
= 10 u
= 10 x 5
= 50
Answer(s): (a) 25; (b) 25; (c) 30; (d) 50