Adam has 4 times as many stickers as Charlie.
After Charlie receives another 30 stickers,
both have equal number of stickers.
- How many stickers does Charlie have in the end?
- How many stickers does Adam have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Charlie |
Before |
4 u |
1 u |
Change |
No change |
+ 30 |
After |
4 u |
4 u |
(a)
The number of stickers Adam has at first and in the end remains unchanged.
Make the numer of stickers that Adam has the same using LCM of 1 and 4.
LCM of 1 and 4 = 4
Number of stickers that Charlie receives
= 4 u - 1 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of stickers that Charlie has in the end
= 4 u
= 4 x 10
= 40
(b)
Number of stickers that Adam has at first
= 4 u
= 4 x 10
= 40
(c)
Number of stickers that they have at first
= 1 u + 4 u
= 5 u
= 5 x 10
= 50
(d)
Number of stickers that they have in the end
= 4 u + 4 u
= 8 u
= 8 x 10
= 80
Answer(s): (a) 40; (b) 40; (c) 50; (d) 80