Adam has 3 times as many stickers as Bryan.
After Bryan receives another 40 stickers,
both have equal number of stickers.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
| |
Adam |
Bryan |
| Before |
3 u |
1 u |
| Change |
No change |
+ 40 |
| After |
3 u |
3 u |
(a)
The number of stickers Adam has at first and in the end remains unchanged.
Make the numer of stickers that Adam has the same using LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of stickers that Bryan receives
= 3 u - 1 u
= 2 u
2 u = 40
1 u = 40 ÷ 2 = 20
Number of stickers that Bryan has in the end
= 3 u
= 3 x 20
= 60
(b)
Number of stickers that Adam has at first
= 3 u
= 3 x 20
= 60
(c)
Number of stickers that they have at first
= 1 u + 3 u
= 4 u
= 4 x 20
= 80
(d)
Number of stickers that they have in the end
= 3 u + 3 u
= 6 u
= 6 x 20
= 120
Answer(s): (a) 60; (b) 60; (c) 80; (d) 120
