Adam has 150 stickers more than Bryan.
After he gives away 110 stickers,
Adam has 5 times as many stickers as Bryan.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
1 u + 150 |
1 u |
Change |
- 110 |
No change |
After |
5 u |
1 u |
(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the number of stickers Bryan has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1
1 u + 150 - 110 = 5 u
1 u + 40 = 5 u
5 u - 1 u = 40
4 u = 40
1 u = 40 ÷ 4 = 10
Number of stickers that Bryan has
= 1 u
= 10
(b)
Number of stickers that Adam has at first
= 1 u + 150
= 10 + 150
= 160
(c)
Number of stickers that they have altogether at first
= 1 u + 1 u + 150
= 4 u + 150
= 4 x 10 + 150
= 40 + 150
= 190
(d)
Number of stickers that they have altogether in the end
= 5 u + 1 u
= 6 u
= 6 x 10
= 60
Answer(s): (a) 10; (b) 160; (c) 190; (d) 60