Adam has 40 stickers more than Bryan.
After he gives away 20 stickers,
Adam has 5 times as many stickers as Bryan.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
| |
Adam |
Bryan |
| Before |
1 u + 40 |
1 u |
| Change |
- 20 |
No change |
| After |
5 u |
1 u |
(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the number of stickers Bryan has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1
1 u + 40 - 20 = 5 u
1 u + 20 = 5 u
5 u - 1 u = 20
4 u = 20
1 u = 20 ÷ 4 = 5
Number of stickers that Bryan has
= 1 u
= 5
(b)
Number of stickers that Adam has at first
= 1 u + 40
= 5 + 40
= 45
(c)
Number of stickers that they have altogether at first
= 1 u + 1 u + 40
= 4 u + 40
= 4 x 5 + 40
= 20 + 40
= 60
(d)
Number of stickers that they have altogether in the end
= 5 u + 1 u
= 6 u
= 6 x 5
= 30
Answer(s): (a) 5; (b) 45; (c) 60; (d) 30
