Adam has 110 stickers more than Bryan.
After he gives away 80 stickers,
Adam has 4 times as many stickers as Bryan.

1. How many stickers does Bryan have?
2. How many stickers does Adam have at first?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Adam	Bryan
Before	1 u + 110	1 u
Change	- 80	No change
After	4 u	1 u

(a)
The number of stickers Bryan has at first and in the end remains unchanged.
Make the number of stickers Bryan has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1

1 u + 110 - 80 = 4 u
1 u + 30 = 4 u
4 u - 1 u = 30
3 u = 30

1 u = 30 ÷ 3 = 10

Number of stickers that Bryan has
= 1 u
= 10

(b)
Number of stickers that Adam has at first
= 1 u + 110
= 10 + 110
= 120

(c)
Number of stickers that they have altogether at first
= 1 u + 1 u + 110
= 3 u + 110
= 3 x 10 + 110
= 30 + 110
= 140

(d)
Number of stickers that they have altogether in the end
= 4 u + 1 u
= 5 u
= 5 x 10
= 50

Answer(s): (a) 10; (b) 120; (c) 140; (d) 50