Bryan has 80 stickers more than Adam.
After he gives away 70 stickers,
Bryan has 3 times as many stickers as Adam.
- How many stickers does Adam have?
- How many stickers does Bryan have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Adam |
Before |
1 u + 80 |
1 u |
Change |
- 70 |
No change |
After |
3 u |
1 u |
(a)
The number of stickers Adam has at first and in the end remains unchanged.
Make the number of stickers Adam has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1
1 u + 80 - 70 = 3 u
1 u + 10 = 3 u
3 u - 1 u = 10
2 u = 10
1 u = 10 ÷ 2 = 5
Number of stickers that Adam has
= 1 u
= 5
(b)
Number of stickers that Bryan has at first
= 1 u + 80
= 5 + 80
= 85
(c)
Number of stickers that they have altogether at first
= 1 u + 1 u + 80
= 2 u + 80
= 2 x 5 + 80
= 10 + 80
= 90
(d)
Number of stickers that they have altogether in the end
= 3 u + 1 u
= 4 u
= 4 x 5
= 20
Answer(s): (a) 5; (b) 85; (c) 90; (d) 20