Adam has 50 more stickers than Bryan.
After Bryan gives away 30 stickers,
Adam has 5 times as many stickers as Bryan.
- How many stickers does Bryan have at first?
- How many stickers does Adam have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
1 u + 30 + 50 |
1 u + 30 |
Change |
No change |
- 30 |
After |
5 u |
1 u |
(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Number of stickers that Adam has at first = Number of stickers that Adam has in the end
1 u + 30 + 50 = 5 u
1 u + 80 = 5 u
5 u - 1 u = 80
4 u = 80
1 u = 80 ÷ 4 = 20
Number of stickers that Bryan has
= 1 u + 30
= 20 + 30
= 50
(b)
Number of stickers that Adam has
= 5 u
= 5 x 20
= 100
(c)
Number of stickers that they have altogether at first
= 1 u + 30 + 50 + 1 u + 30
= 1 u + 1 u + 30 + 50 + 30
= 2 u + 110
= 2 x 20 + 110
= 40 + 110
= 150
(d)
Number of stickers that they have altogether in the end
= 5 u + 1 u
= 6 u
= 6 x 20
= 120
Answer(s): (a) 50; (b) 100; (c) 150; (d) 120