Charlie has 50 more stickers than Bryan.
After Bryan gives away 40 stickers,
Charlie has 4 times as many stickers as Bryan.

1. How many stickers does Bryan have at first?
2. How many stickers does Charlie have?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Charlie	Bryan
Before	1 u + 40 + 50	1 u + 40
Change	No change	- 40
After	4 u	1 u

(a)
The number of stickers that Charlie has at first and in the end remains unchanged.
Number of stickers that Charlie has at first = Number of stickers that Charlie has in the end

1 u + 40 + 50 = 4 u
1 u + 90 = 4 u
4 u - 1 u = 90
3 u = 90

1 u = 90 ÷ 3 = 30

Number of stickers that Bryan has
= 1 u + 40
= 30 + 40
= 70

(b)
Number of stickers that Charlie has
= 4 u
= 4 x 30
= 120

(c)
Number of stickers that they have altogether at first
= 1 u + 40 + 50 + 1 u + 40
= 1 u + 1 u + 40 + 50 + 40
= 2 u + 130
= 2 x 30 + 130
= 60 + 130
= 190

(d)
Number of stickers that they have altogether in the end
= 4 u + 1 u
= 5 u
= 5 x 30
= 150

Answer(s): (a) 70; (b) 120; (c) 190; (d) 150