Bryan has 60 more stickers than Adam.
After Adam gives away 30 stickers,
Bryan has 4 times as many stickers as Adam.
- How many stickers does Adam have at first?
- How many stickers does Bryan have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Adam |
Before |
1 u + 30 + 60 |
1 u + 30 |
Change |
No change |
- 30 |
After |
4 u |
1 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Number of stickers that Bryan has at first = Number of stickers that Bryan has in the end
1 u + 30 + 60 = 4 u
1 u + 90 = 4 u
4 u - 1 u = 90
3 u = 90
1 u = 90 ÷ 3 = 30
Number of stickers that Adam has
= 1 u + 30
= 30 + 30
= 60
(b)
Number of stickers that Bryan has
= 4 u
= 4 x 30
= 120
(c)
Number of stickers that they have altogether at first
= 1 u + 30 + 60 + 1 u + 30
= 1 u + 1 u + 30 + 60 + 30
= 2 u + 120
= 2 x 30 + 120
= 60 + 120
= 180
(d)
Number of stickers that they have altogether in the end
= 4 u + 1 u
= 5 u
= 5 x 30
= 150
Answer(s): (a) 60; (b) 120; (c) 180; (d) 150