Bryan has 40 more stickers than Adam.
After Adam gives away 30 stickers,
Bryan has 3 times as many stickers as Adam.
- How many stickers does Adam have at first?
- How many stickers does Bryan have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Adam |
Before |
1 u + 30 + 40 |
1 u + 30 |
Change |
No change |
- 30 |
After |
3 u |
1 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Number of stickers that Bryan has at first = Number of stickers that Bryan has in the end
1 u + 30 + 40 = 3 u
1 u + 70 = 3 u
3 u - 1 u = 70
2 u = 70
1 u = 70 ÷ 2 = 35
Number of stickers that Adam has
= 1 u + 30
= 35 + 30
= 65
(b)
Number of stickers that Bryan has
= 3 u
= 3 x 35
= 105
(c)
Number of stickers that they have altogether at first
= 1 u + 30 + 40 + 1 u + 30
= 1 u + 1 u + 30 + 40 + 30
= 2 u + 100
= 2 x 35 + 100
= 70 + 100
= 170
(d)
Number of stickers that they have altogether in the end
= 3 u + 1 u
= 4 u
= 4 x 35
= 140
Answer(s): (a) 65; (b) 105; (c) 170; (d) 140