Bryan has 50 more stickers than Charlie.
After Charlie gives away 40 stickers,
Bryan has 4 times as many stickers as Charlie.

1. How many stickers does Charlie have at first?
2. How many stickers does Bryan have?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Bryan	Charlie
Before	1 u + 40 + 50	1 u + 40
Change	No change	- 40
After	4 u	1 u

(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Number of stickers that Bryan has at first = Number of stickers that Bryan has in the end

1 u + 40 + 50 = 4 u
1 u + 90 = 4 u
4 u - 1 u = 90
3 u = 90

1 u = 90 ÷ 3 = 30

Number of stickers that Charlie has
= 1 u + 40
= 30 + 40
= 70

(b)
Number of stickers that Bryan has
= 4 u
= 4 x 30
= 120

(c)
Number of stickers that they have altogether at first
= 1 u + 40 + 50 + 1 u + 40
= 1 u + 1 u + 40 + 50 + 40
= 2 u + 130
= 2 x 30 + 130
= 60 + 130
= 190

(d)
Number of stickers that they have altogether in the end
= 4 u + 1 u
= 5 u
= 5 x 30
= 150

Answer(s): (a) 70; (b) 120; (c) 190; (d) 150