Charlie has 70 more stickers than Adam.
After Adam gives away 30 stickers,
Charlie has 5 times as many stickers as Adam.
- How many stickers does Adam have at first?
- How many stickers does Charlie have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Charlie |
Adam |
Before |
1 u + 30 + 70 |
1 u + 30 |
Change |
No change |
- 30 |
After |
5 u |
1 u |
(a)
The number of stickers that Charlie has at first and in the end remains unchanged.
Number of stickers that Charlie has at first = Number of stickers that Charlie has in the end
1 u + 30 + 70 = 5 u
1 u + 100 = 5 u
5 u - 1 u = 100
4 u = 100
1 u = 100 ÷ 4 = 25
Number of stickers that Adam has
= 1 u + 30
= 25 + 30
= 55
(b)
Number of stickers that Charlie has
= 5 u
= 5 x 25
= 125
(c)
Number of stickers that they have altogether at first
= 1 u + 30 + 70 + 1 u + 30
= 1 u + 1 u + 30 + 70 + 30
= 2 u + 130
= 2 x 25 + 130
= 50 + 130
= 180
(d)
Number of stickers that they have altogether in the end
= 5 u + 1 u
= 6 u
= 6 x 25
= 150
Answer(s): (a) 55; (b) 125; (c) 180; (d) 150