Adam has 30 more stickers than Bryan.
After Bryan gives away 30 stickers,
Adam has 3 times as many stickers as Bryan.
- How many stickers does Bryan have at first?
- How many stickers does Adam have?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
1 u + 30 + 30 |
1 u + 30 |
Change |
No change |
- 30 |
After |
3 u |
1 u |
(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Number of stickers that Adam has at first = Number of stickers that Adam has in the end
1 u + 30 + 30 = 3 u
1 u + 60 = 3 u
3 u - 1 u = 60
2 u = 60
1 u = 60 ÷ 2 = 30
Number of stickers that Bryan has
= 1 u + 30
= 30 + 30
= 60
(b)
Number of stickers that Adam has
= 3 u
= 3 x 30
= 90
(c)
Number of stickers that they have altogether at first
= 1 u + 30 + 30 + 1 u + 30
= 1 u + 1 u + 30 + 30 + 30
= 2 u + 90
= 2 x 30 + 90
= 60 + 90
= 150
(d)
Number of stickers that they have altogether in the end
= 3 u + 1 u
= 4 u
= 4 x 30
= 120
Answer(s): (a) 60; (b) 90; (c) 150; (d) 120