Adam has 50 more stickers than Bryan.
After Bryan gives away 20 stickers,
Adam has 3 times as many stickers as Bryan.

1. How many stickers does Bryan have at first?
2. How many stickers does Adam have?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Adam	Bryan
Before	1 u + 20 + 50	1 u + 20
Change	No change	- 20
After	3 u	1 u

(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Number of stickers that Adam has at first = Number of stickers that Adam has in the end

1 u + 20 + 50 = 3 u
1 u + 70 = 3 u
3 u - 1 u = 70
2 u = 70

1 u = 70 ÷ 2 = 35

Number of stickers that Bryan has
= 1 u + 20
= 35 + 20
= 55

(b)
Number of stickers that Adam has
= 3 u
= 3 x 35
= 105

(c)
Number of stickers that they have altogether at first
= 1 u + 20 + 50 + 1 u + 20
= 1 u + 1 u + 20 + 50 + 20
= 2 u + 90
= 2 x 35 + 90
= 70 + 90
= 160

(d)
Number of stickers that they have altogether in the end
= 3 u + 1 u
= 4 u
= 4 x 35
= 140

Answer(s): (a) 55; (b) 105; (c) 160; (d) 140