Bryan has 30 more stickers than Adam.
After Adam gives away 30 stickers,
Bryan has 3 times as many stickers as Adam.

1. How many stickers does Adam have at first?
2. How many stickers does Bryan have?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Bryan	Adam
Before	1 u + 30 + 30	1 u + 30
Change	No change	- 30
After	3 u	1 u

(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Number of stickers that Bryan has at first = Number of stickers that Bryan has in the end

1 u + 30 + 30 = 3 u
1 u + 60 = 3 u
3 u - 1 u = 60
2 u = 60

1 u = 60 ÷ 2 = 30

Number of stickers that Adam has
= 1 u + 30
= 30 + 30
= 60

(b)
Number of stickers that Bryan has
= 3 u
= 3 x 30
= 90

(c)
Number of stickers that they have altogether at first
= 1 u + 30 + 30 + 1 u + 30
= 1 u + 1 u + 30 + 30 + 30
= 2 u + 90
= 2 x 30 + 90
= 60 + 90
= 150

(d)
Number of stickers that they have altogether in the end
= 3 u + 1 u
= 4 u
= 4 x 30
= 120

Answer(s): (a) 60; (b) 90; (c) 150; (d) 120