Charlie has 80 more stickers than Adam.
After Adam gives away 20 stickers,
Charlie has 5 times as many stickers as Adam.

1. How many stickers does Adam have at first?
2. How many stickers does Charlie have?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Charlie	Adam
Before	1 u + 20 + 80	1 u + 20
Change	No change	- 20
After	5 u	1 u

(a)
The number of stickers that Charlie has at first and in the end remains unchanged.
Number of stickers that Charlie has at first = Number of stickers that Charlie has in the end

1 u + 20 + 80 = 5 u
1 u + 100 = 5 u
5 u - 1 u = 100
4 u = 100

1 u = 100 ÷ 4 = 25

Number of stickers that Adam has
= 1 u + 20
= 25 + 20
= 45

(b)
Number of stickers that Charlie has
= 5 u
= 5 x 25
= 125

(c)
Number of stickers that they have altogether at first
= 1 u + 20 + 80 + 1 u + 20
= 1 u + 1 u + 20 + 80 + 20
= 2 u + 120
= 2 x 25 + 120
= 50 + 120
= 170

(d)
Number of stickers that they have altogether in the end
= 5 u + 1 u
= 6 u
= 6 x 25
= 150

Answer(s): (a) 45; (b) 125; (c) 170; (d) 150