Bryan has 30 stickers more than Adam.
After Bryan gives away 40 stickers,
Adam has 3 times as many stickers as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Adam |
Before |
3 u + 30 |
3 u |
Change |
- 40 |
No change |
After |
1 u |
3 u |
(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Make the number of stickers that Adam has the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
3 u + 30 - 40 = 1 u
3 u - 10 = 1 u
3 u - 1 u = 10
2 u = 10
1 u = 10 ÷ 2 = 5
Number of stickers that Adam has
= 3 u
= 3 x 5
= 15
(b)
Number of stickers that Bryan has at first
= 3 u + 30
= 15 + 30
= 45
(c)
Number of stickers that they have altogether at first
= 3 u + 30 + 3 u
= 6 u + 30
= 6 x 5 + 30
= 30 + 30
= 60
(d)
Number of stickers that they have altogether in the end
= 1 u + 3 u
= 4 u
= 4 x 5
= 20
Answer(s): (a) 15; (b) 45; (c) 60; (d) 20