Adam has 80 stickers more than Bryan.
After Adam gives away 90 stickers,
Bryan has 3 times as many stickers as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
3 u + 80 |
3 u |
Change |
- 90 |
No change |
After |
1 u |
3 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
3 u + 80 - 90 = 1 u
3 u - 10 = 1 u
3 u - 1 u = 10
2 u = 10
1 u = 10 ÷ 2 = 5
Number of stickers that Bryan has
= 3 u
= 3 x 5
= 15
(b)
Number of stickers that Adam has at first
= 3 u + 80
= 15 + 80
= 95
(c)
Number of stickers that they have altogether at first
= 3 u + 80 + 3 u
= 6 u + 80
= 6 x 5 + 80
= 30 + 80
= 110
(d)
Number of stickers that they have altogether in the end
= 1 u + 3 u
= 4 u
= 4 x 5
= 20
Answer(s): (a) 15; (b) 95; (c) 110; (d) 20