Bryan has 20 stickers more than Adam.
After Bryan gives away 40 stickers,
Adam has 3 times as many stickers as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Adam |
Before |
3 u + 20 |
3 u |
Change |
- 40 |
No change |
After |
1 u |
3 u |
(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Make the number of stickers that Adam has the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
3 u + 20 - 40 = 1 u
3 u - 20 = 1 u
3 u - 1 u = 20
2 u = 20
1 u = 20 ÷ 2 = 10
Number of stickers that Adam has
= 3 u
= 3 x 10
= 30
(b)
Number of stickers that Bryan has at first
= 3 u + 20
= 30 + 20
= 50
(c)
Number of stickers that they have altogether at first
= 3 u + 20 + 3 u
= 6 u + 20
= 6 x 10 + 20
= 60 + 20
= 80
(d)
Number of stickers that they have altogether in the end
= 1 u + 3 u
= 4 u
= 4 x 10
= 40
Answer(s): (a) 30; (b) 50; (c) 80; (d) 40