Bryan has 60 stickers more than Adam.
After Bryan gives away 100 stickers,
Adam has 5 times as many stickers as Bryan.

1. How many stickers does Adam have?
2. How many stickers does Bryan have at first?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Bryan	Adam
Before	5 u + 60	5 u
Change	- 100	No change
After	1 u	5 u

(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Make the number of stickers that Adam has the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5

5 u + 60 - 100 = 1 u
5 u - 40 = 1 u
5 u - 1 u = 40
4 u = 40

1 u = 40 ÷ 4 = 10

Number of stickers that Adam has
= 5 u
= 5 x 10
= 50

(b)
Number of stickers that Bryan has at first
= 5 u + 60
= 50 + 60
= 110

(c)
Number of stickers that they have altogether at first
= 5 u + 60 + 5 u
= 10 u + 60
= 10 x 10 + 60
= 100 + 60
= 160

(d)
Number of stickers that they have altogether in the end
= 1 u + 5 u
= 6 u
= 6 x 10
= 60

Answer(s): (a) 50; (b) 110; (c) 160; (d) 60