Adam has 50 stickers more than Bryan.
After Adam gives away 80 stickers,
Bryan has 4 times as many stickers as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
4 u + 50 |
4 u |
Change |
- 80 |
No change |
After |
1 u |
4 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using the LCM of 1 and 4.
LCM of 1 and 4 = 4
4 u + 50 - 80 = 1 u
4 u - 30 = 1 u
4 u - 1 u = 30
3 u = 30
1 u = 30 ÷ 3 = 10
Number of stickers that Bryan has
= 4 u
= 4 x 10
= 40
(b)
Number of stickers that Adam has at first
= 4 u + 50
= 40 + 50
= 90
(c)
Number of stickers that they have altogether at first
= 4 u + 50 + 4 u
= 8 u + 50
= 8 x 10 + 50
= 80 + 50
= 130
(d)
Number of stickers that they have altogether in the end
= 1 u + 4 u
= 5 u
= 5 x 10
= 50
Answer(s): (a) 40; (b) 90; (c) 130; (d) 50