Adam has 30 stickers more than Bryan.
After Adam gives away 70 stickers,
Bryan has 5 times as many stickers as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
5 u + 30 |
5 u |
Change |
- 70 |
No change |
After |
1 u |
5 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5
5 u + 30 - 70 = 1 u
5 u - 40 = 1 u
5 u - 1 u = 40
4 u = 40
1 u = 40 ÷ 4 = 10
Number of stickers that Bryan has
= 5 u
= 5 x 10
= 50
(b)
Number of stickers that Adam has at first
= 5 u + 30
= 50 + 30
= 80
(c)
Number of stickers that they have altogether at first
= 5 u + 30 + 5 u
= 10 u + 30
= 10 x 10 + 30
= 100 + 30
= 130
(d)
Number of stickers that they have altogether in the end
= 1 u + 5 u
= 6 u
= 6 x 10
= 60
Answer(s): (a) 50; (b) 80; (c) 130; (d) 60