Bryan has 70 stickers more than Adam.
After Bryan gives away 80 stickers,
Adam has 3 times as many stickers as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Bryan |
Adam |
Before |
3 u + 70 |
3 u |
Change |
- 80 |
No change |
After |
1 u |
3 u |
(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Make the number of stickers that Adam has the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
3 u + 70 - 80 = 1 u
3 u - 10 = 1 u
3 u - 1 u = 10
2 u = 10
1 u = 10 ÷ 2 = 5
Number of stickers that Adam has
= 3 u
= 3 x 5
= 15
(b)
Number of stickers that Bryan has at first
= 3 u + 70
= 15 + 70
= 85
(c)
Number of stickers that they have altogether at first
= 3 u + 70 + 3 u
= 6 u + 70
= 6 x 5 + 70
= 30 + 70
= 100
(d)
Number of stickers that they have altogether in the end
= 1 u + 3 u
= 4 u
= 4 x 5
= 20
Answer(s): (a) 15; (b) 85; (c) 100; (d) 20