Adam has 30 stickers more than Bryan.
After Adam gives away 50 stickers,
Bryan has 3 times as many stickers as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
3 u + 30 |
3 u |
Change |
- 50 |
No change |
After |
1 u |
3 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
3 u + 30 - 50 = 1 u
3 u - 20 = 1 u
3 u - 1 u = 20
2 u = 20
1 u = 20 ÷ 2 = 10
Number of stickers that Bryan has
= 3 u
= 3 x 10
= 30
(b)
Number of stickers that Adam has at first
= 3 u + 30
= 30 + 30
= 60
(c)
Number of stickers that they have altogether at first
= 3 u + 30 + 3 u
= 6 u + 30
= 6 x 10 + 30
= 60 + 30
= 90
(d)
Number of stickers that they have altogether in the end
= 1 u + 3 u
= 4 u
= 4 x 10
= 40
Answer(s): (a) 30; (b) 60; (c) 90; (d) 40