Adam has 70 stickers more than Bryan.
After Adam gives away 90 stickers,
Bryan has 5 times as many stickers as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
5 u + 70 |
5 u |
Change |
- 90 |
No change |
After |
1 u |
5 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5
5 u + 70 - 90 = 1 u
5 u - 20 = 1 u
5 u - 1 u = 20
4 u = 20
1 u = 20 ÷ 4 = 5
Number of stickers that Bryan has
= 5 u
= 5 x 5
= 25
(b)
Number of stickers that Adam has at first
= 5 u + 70
= 25 + 70
= 95
(c)
Number of stickers that they have altogether at first
= 5 u + 70 + 5 u
= 10 u + 70
= 10 x 5 + 70
= 50 + 70
= 120
(d)
Number of stickers that they have altogether in the end
= 1 u + 5 u
= 6 u
= 6 x 5
= 30
Answer(s): (a) 25; (b) 95; (c) 120; (d) 30