Adam has 8 times as many stickers as Bryan.
After Adam gives away half of his stickers,
he has 30 stickers more than Bryan.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
8 u |
1 u |
Change |
- 4 u |
No change |
After |
4 u |
1 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1
Number of stickers that Adam has more than Bryan in the end
= 4 u - 1 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of stickers that Bryan has
= 1 u
= 10
(b)
Number of stickers that Adam has at first
= 8 u
= 8 x 10
= 80
(c)
Number of stickers that they have altogether at first
= 8 u + 1 u
= 9 u
= 9 x 10
= 90
(d)
Number of stickers that they have altogether in the end
= 4 u + 1 u
= 5 u
= 5 x 10
= 50
Answer(s): (a) 10; (b) 80; (c) 90; (d) 50