Adam has 10 times as many stickers as Bryan.
After Adam gives away half of his stickers,
he has 40 stickers more than Bryan.
- How many stickers does Bryan have?
- How many stickers does Adam have at first?
- How many stickers do they have altogether at first?
- How many stickers do they have altogether in the end?
|
Adam |
Bryan |
Before |
10 u |
1 u |
Change |
- 5 u |
No change |
After |
5 u |
1 u |
(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1
Number of stickers that Adam has more than Bryan in the end
= 5 u - 1 u
= 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Number of stickers that Bryan has
= 1 u
= 10
(b)
Number of stickers that Adam has at first
= 10 u
= 10 x 10
= 100
(c)
Number of stickers that they have altogether at first
= 10 u + 1 u
= 11 u
= 11 x 10
= 110
(d)
Number of stickers that they have altogether in the end
= 5 u + 1 u
= 6 u
= 6 x 10
= 60
Answer(s): (a) 10; (b) 100; (c) 110; (d) 60