Bryan has 8 times as many stickers as Adam.
After Bryan gives away half of his stickers,
he has 30 stickers more than Adam.

1. How many stickers does Adam have?
2. How many stickers does Bryan have at first?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Bryan	Adam
Before	8 u	1 u
Change	- 4 u	No change
After	4 u	1 u

(a)
The number of stickers that Adam has at first and in the end remains unchanged.
Make the number of stickers that Adam has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1

Number of stickers that Bryan has more than Adam in the end
= 4 u - 1 u
= 3 u

3 u = 30
1 u = 30 ÷ 3 = 10

Number of stickers that Adam has
= 1 u
= 10

(b)
Number of stickers that Bryan has at first
= 8 u
= 8 x 10
= 80

(c)
Number of stickers that they have altogether at first
= 8 u + 1 u
= 9 u
= 9 x 10
= 90

(d)
Number of stickers that they have altogether in the end
= 4 u + 1 u
= 5 u
= 5 x 10
= 50

Answer(s): (a) 10; (b) 80; (c) 90; (d) 50