Adam has 8 times as many stickers as Bryan.
After Adam gives away half of his stickers,
he has 30 stickers more than Bryan.

1. How many stickers does Bryan have?
2. How many stickers does Adam have at first?
3. How many stickers do they have altogether at first?
4. How many stickers do they have altogether in the end?

	Adam	Bryan
Before	8 u	1 u
Change	- 4 u	No change
After	4 u	1 u

(a)
The number of stickers that Bryan has at first and in the end remains unchanged.
Make the number of stickers that Bryan has the same using LCM of 1 and 1.
LCM of 1 and 1 = 1

Number of stickers that Adam has more than Bryan in the end
= 4 u - 1 u
= 3 u

3 u = 30
1 u = 30 ÷ 3 = 10

Number of stickers that Bryan has
= 1 u
= 10

(b)
Number of stickers that Adam has at first
= 8 u
= 8 x 10
= 80

(c)
Number of stickers that they have altogether at first
= 8 u + 1 u
= 9 u
= 9 x 10
= 90

(d)
Number of stickers that they have altogether in the end
= 4 u + 1 u
= 5 u
= 5 x 10
= 50

Answer(s): (a) 10; (b) 80; (c) 90; (d) 50