Adam has 600 blue and red stickers.
He sells 60 blue stickers and the number of red stickers becomes 2 times as many as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Blue |
Red |
Before |
1 u + 60 |
2 u |
Change |
- 60 |
No Change |
After |
1 u |
2 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 60 + 2 u
= 3 u + 60
3 u + 60 = 600
3 u = 600 - 60
3 u = 540
1 u = 540 ÷ 3 = 180
Number of more red stickers than blue stickers at first
= 2 u - (1 u + 60)
= 2 u - 1 u - 60
= 1 u - 60
= 1 x 180 - 60
= 180 - 60
= 120
(b)
Number of less blue stickers than red stickers in the end
= 2 u - 1 u
= 1 u
= 1 x 180
= 180
Answer(s): (a) 120; (b) 180