Adam has 200 green and blue stickers.
He sells 40 green stickers and the number of blue stickers becomes 3 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Green |
Blue |
Before |
1 u + 40 |
3 u |
Change |
- 40 |
No Change |
After |
1 u |
3 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 40 + 3 u
= 4 u + 40
4 u + 40 = 200
4 u = 200 - 40
4 u = 160
1 u = 160 ÷ 4 = 40
Number of more blue stickers than green stickers at first
= 3 u - (1 u + 40)
= 3 u - 1 u - 40
= 2 u - 40
= 2 x 40 - 40
= 80 - 40
= 40
(b)
Number of less green stickers than blue stickers in the end
= 3 u - 1 u
= 2 u
= 2 x 40
= 80
Answer(s): (a) 40; (b) 80