Adam has 300 green and blue stickers.
He sells 60 green stickers and the number of blue stickers becomes 5 times as many as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Green |
Blue |
Before |
1 u + 60 |
5 u |
Change |
- 60 |
No Change |
After |
1 u |
5 u |
(a)
The number of blue stickers remains unchanged.
Total number of stickers at first
= 1 u + 60 + 5 u
= 6 u + 60
6 u + 60 = 300
6 u = 300 - 60
6 u = 240
1 u = 240 ÷ 6 = 40
Number of more blue stickers than green stickers at first
= 5 u - (1 u + 60)
= 5 u - 1 u - 60
= 4 u - 60
= 4 x 40 - 60
= 160 - 60
= 100
(b)
Number of less green stickers than blue stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 40
= 160
Answer(s): (a) 100; (b) 160