Adam has 600 blue and red stickers.
He sells 20 blue stickers and the number of red stickers becomes 4 times as many as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Blue |
Red |
Before |
1 u + 20 |
4 u |
Change |
- 20 |
No Change |
After |
1 u |
4 u |
(a)
The number of red stickers remains unchanged.
Total number of stickers at first
= 1 u + 20 + 4 u
= 5 u + 20
5 u + 20 = 600
5 u = 600 - 20
5 u = 580
1 u = 580 ÷ 5 = 116
Number of more red stickers than blue stickers at first
= 4 u - (1 u + 20)
= 4 u - 1 u - 20
= 3 u - 20
= 3 x 116 - 20
= 348 - 20
= 328
(b)
Number of less blue stickers than red stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 116
= 348
Answer(s): (a) 328; (b) 348