Adam has 700 red and green stickers.
He sells 40 red stickers and the number of green stickers becomes 4 times as many as red stickers.
- How many more green stickers than red stickers does Adam have at first?
- How many less red stickers than green stickers does Adam have in the end?
|
Red |
Green |
Before |
1 u + 40 |
4 u |
Change |
- 40 |
No Change |
After |
1 u |
4 u |
(a)
The number of green stickers remains unchanged.
Total number of stickers at first
= 1 u + 40 + 4 u
= 5 u + 40
5 u + 40 = 700
5 u = 700 - 40
5 u = 660
1 u = 660 ÷ 5 = 132
Number of more green stickers than red stickers at first
= 4 u - (1 u + 40)
= 4 u - 1 u - 40
= 3 u - 40
= 3 x 132 - 40
= 396 - 40
= 356
(b)
Number of less red stickers than green stickers in the end
= 4 u - 1 u
= 3 u
= 3 x 132
= 396
Answer(s): (a) 356; (b) 396