Adam has 200 red and green stickers.
He sells 50 red stickers and the number of green stickers becomes 5 times as many as red stickers.
- How many more green stickers than red stickers does Adam have at first?
- How many less red stickers than green stickers does Adam have in the end?
|
Red |
Green |
Before |
1 u + 50 |
5 u |
Change |
- 50 |
No Change |
After |
1 u |
5 u |
(a)
The number of green stickers remains unchanged.
Total number of stickers at first
= 1 u + 50 + 5 u
= 6 u + 50
6 u + 50 = 200
6 u = 200 - 50
6 u = 150
1 u = 150 ÷ 6 = 25
Number of more green stickers than red stickers at first
= 5 u - (1 u + 50)
= 5 u - 1 u - 50
= 4 u - 50
= 4 x 25 - 50
= 100 - 50
= 50
(b)
Number of less red stickers than green stickers in the end
= 5 u - 1 u
= 4 u
= 4 x 25
= 100
Answer(s): (a) 50; (b) 100